如何解决函数输入参数必须小于32的限制

create view test_view (p1,p2) as select cast(null as int),cast(null asint) 

create or replace function test_rec1(int,int) returns  test_view as  
''  
declare  
view_rec test_view%rowtype ; 
view_rec1 test_view%rowtype ; 
begin  
view_rec.p1 = 2; 
view_rec.p2 = 3; 
select * into view_rec1 from test_rec2( test_rec3($1),$2); 
return view_rec1; 
end;''language ''plpgsql'';  

create or replace function test_rec2(test_view,int) returns  test_view as  
''  
declare  
view_return alias for $1; 
begin  

view_return.p2 = $2; 
return view_return; 

end;''language ''plpgsql'';  

create or replace function test_rec3(int) returns  test_view as  
''  
declare  
view_return test_view%rowtype; 
begin  
view_return.p1 = $1; 
view_return.p2 =0; 
return view_return; 

end;''language ''plpgsql'';